JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Nucleus (Stability and Reaction)

  • question_answer
    In the sequence of following nuclear reactions \[_{92}{{X}^{238}}\xrightarrow{-\alpha }Y\xrightarrow{-\beta }Z\xrightarrow{-\beta }L{{\xrightarrow{-n\alpha }}_{84}}{{M}^{218}}\]                 The value of \[n\] will be                                              [MP PMT 1999]

    A)                 3             

    B)                 4

    C)                 5             

    D)                 6

    Correct Answer: B

    Solution :

              The value of \[n=\frac{238-218}{4}=\frac{20}{4}=5-1=4\]


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