A) \[_{-1}{{e}^{0}}\]
B) \[_{+1}{{e}^{0}}\]
C) \[_{1}{{H}^{1}}\]
D) \[_{0}{{n}^{1}}\]
Correct Answer: B
Solution :
\[_{+1}{{e}^{o}}\] is positron.
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