A) Neutron
B) Deutron
C) \[\alpha \]-particle
D) Positron
Correct Answer: A
Solution :
\[_{11}N{{a}^{23}}+{{\,}_{1}}{{H}^{1}}\to {{\,}_{12}}M{{g}^{23}}+{{\,}_{0}}{{n}^{1}}\]You need to login to perform this action.
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