A) \[_{19}^{41}K\]
B) \[_{21}^{43}Sc\]
C) \[_{21}^{40}Sc\]
D) \[_{20}^{42}Ca\]
Correct Answer: C
Solution :
\[_{18}^{40}Ar\] having 40 ? 18 = 22 neutrons While \[_{21}^{40}Sc\] having 40 ? 21 = 19 neutrons.
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