A) \[_{11}^{22}Na\]
B) \[_{11}^{23}Na\]
C) \[_{12}^{23}Mg\]
D) \[_{12}^{26}Mg\]
Correct Answer: A
Solution :
\[_{12}^{24}Mg{{+}_{1}}{{D}^{2}}\to {{\,}_{2}}H{{e}^{4}}+_{11}^{22}Na\]You need to login to perform this action.
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