A) \[_{17}C{{l}^{35}}\]
B) \[_{19}{{K}^{27}}\]
C) \[_{17}C{{l}^{37}}\]
D) \[_{19}{{K}^{39}}\]
Correct Answer: C
Solution :
\[_{17}C{{l}^{37}}+{{\,}_{1}}{{H}^{2}}\to {{\,}_{18}}A{{r}^{38}}+{{\,}_{0}}{{n}^{1}}\]You need to login to perform this action.
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