A) 36th
B) 38th
C) 35th
D) 48th
Correct Answer: B
Solution :
[b] The 24th term of the sequence 6, 13, 20, 27,... \[=6+(24-1)\,7=6+23\times 7\] \[=6+161=167\] Let the required nth term \[=167+98=265\] \[\therefore \] \[265=6+\text{(}n-1)7\] \[\Rightarrow \] \[(n-1)\times 7=265-6=259\] \[\Rightarrow \] \[(n-1)=\frac{259}{7}=37\] \[\therefore \] \[n=38\] |
You need to login to perform this action.
You will be redirected in
3 sec