7th Class Mathematics Integers Question Bank Number System

  • question_answer
    The multiplicative inverse of \[\frac{97}{89}\] is

    A)  \[\frac{97}{89}\]                      

    B)  \[\frac{89}{97}\]

    C)  \[\frac{1}{97}\]                                    

    D)  \[\frac{1}{89}\]

    Correct Answer: B

    Solution :

                 (b): M.I. \[=\frac{1}{97/89}=\frac{89}{97}.\]


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