A) \[m-n+1=0\]
B) \[m+n-1=0\]
C) \[m+n+1=0\]
D) \[m-n-1=0\]
Correct Answer: D
Solution :
(d): \[{{m}^{2}}=m+3\] \[{{n}^{2}}=3-n\] Solving for m & n and then Subtracting m & n We get \[m-n=1\] \[\Rightarrow m-n-1=0.\]You need to login to perform this action.
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