A) \[x-3\]
B) \[x+3\]
C) \[x-1\]
D) \[x+1\]
Correct Answer: A
Solution :
By applying factor theorem, If \[(x-3)\] is a factor of polynomial \[P(x)={{x}^{2}}-x-6,\]then remainder\[P(3)=0\] \[P(3)={{3}^{2}}-3-6\] \[=9-3-6\] \[=9-9=0\] \[\therefore \] \[(x-3)\] is a factor of polynomial\[P(x)\].You need to login to perform this action.
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