A) \[\frac{S-10}{5}\]
B) \[\frac{S-4}{4}\]
C) \[\frac{S+5}{4}\]
D) \[\frac{S+10}{5}\]
Correct Answer: D
Solution :
(d): Sum of five consecutive integers = S \[\therefore Third\text{ }integer=\frac{S}{5};\] \[\therefore Largest\text{ }integer=\frac{S}{5}+2=\frac{S+10}{5}\]You need to login to perform this action.
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