A) \[\sqrt{2}\]
B) \[\sqrt{4}\]
C) \[\sqrt{9}\]
D) \[\sqrt{16}\]
Correct Answer: A
Solution :
\[\sqrt{2}\]is not a rational number Since, 2 cannot be expressed as a square of any rational number. \[\sqrt{4}=\sqrt{{{2}^{2}}}=2;\sqrt{9}=\sqrt{{{3}^{2}}}=3;\] \[\sqrt{16}=\sqrt{{{4}^{2}}}=4\]
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