A) \[\sqrt{17}-\sqrt{12}\]
B) \[\sqrt{11}-\sqrt{6}\]
C) Both are equal
D) Can't be compared
Correct Answer: B
Solution :
\[\sqrt{11}-\sqrt{6}=3.3-2.4=0.9\] and \[\sqrt{17}-\sqrt{12}=4.1-3.4=0.7\] So, \[\sqrt{11}-\sqrt{16}\]is greater.You need to login to perform this action.
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