A) \[a=1,b=2\]
B) a = 2,b = 1
C) a = 2, b = 3
D) a = 3, b = 2
Correct Answer: B
Solution :
We have, \[a-b\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}\] \[=\frac{(\sqrt{3}-1)}{(\sqrt{3}+1)}\times \frac{(\sqrt{3}-1)}{\sqrt{3}+1}=\frac{{{(\sqrt{3}-1)}^{2}}}{3-1}\] \[=\frac{3+1-2\sqrt{3}}{2}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}\] On comparing, we get \[a=2,b=1\]You need to login to perform this action.
You will be redirected in
3 sec