A) \[8\sqrt{3}\]
B) 14
C) 49
D) 48
Correct Answer: B
Solution :
We have, \[x=7+4\sqrt{3}\] Now, \[\frac{1}{x}=\frac{1}{7+4\sqrt{3}}\times \frac{7-4\sqrt{3}}{7-4\sqrt{3}}\] \[=\frac{7-4\sqrt{3}}{49-48}=7-4\sqrt{3}\] \[\therefore \]\[x+\frac{1}{x}=7+4\sqrt{3}+7-4\sqrt{3}=14\]You need to login to perform this action.
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