A) \[1\]
B) \[0\]
C) \[\frac{2}{1-a}\]
D) \[1+a\]
Correct Answer: C
Solution :
\[\frac{\sqrt{a}+\frac{1}{\sqrt{a}}}{1-a}+\frac{1-\frac{1}{\sqrt{a}}}{1+\sqrt{a}}\] \[=\frac{a+1}{\sqrt{a}(1-a)}+\frac{\sqrt{a}-1}{\sqrt{a}\left( 1+\sqrt{a} \right)}\] \[=\frac{2\sqrt{a}\left( \sqrt{a}+1 \right)}{\sqrt{a}(1-a)\left( 1+\sqrt{a} \right)}=\frac{2}{1-a}\]
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