A) \[\sqrt[5]{{{a}^{3}}{{b}^{2}}c}\]
B) \[\sqrt[4]{{{a}^{3}}{{b}^{2}}c}\]
C) \[\sqrt[3]{{{a}^{3}}{{b}^{2}}c}\]
D) \[\sqrt{{{a}^{3}}{{b}^{2}}c}\]
Correct Answer: A
Solution :
Rationalizing factor of \[\sqrt[n]{{{a}^{p}}}\]is \[\sqrt[n]{{{a}^{n-p}}}\]or \[{{a}^{1\frac{p}{n}}}\]where \[n>p.\] \[\therefore \]R.F. of \[\sqrt[5]{{{a}^{2}}{{b}^{3}}{{c}^{4}}}=\sqrt[5]{{{a}^{3}}{{b}^{2}}c}\]
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