A) \[2\]
B) \[4\]
C) \[8\]
D) \[9\]
Correct Answer: B
Solution :
\[x=\sqrt[3]{2+\sqrt{3}}\] \[\Rightarrow \]\[{{x}^{3}}=2+\sqrt{3}\]and \[\frac{1}{{{x}^{3}}}=2-\sqrt{3}\] \[\therefore \]\[{{x}^{3}}+\frac{1}{{{x}^{3}}}=2+\sqrt{3}+2-\sqrt{3}=4\]You need to login to perform this action.
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