A) 25
B) 26
C) 42
D) 41
Correct Answer: A
Solution :
[a] Let, positive number \[=x\] |
According to the question, |
\[x\times 21={{x}^{2}}-100\] |
\[\Rightarrow \] \[{{x}^{2}}-21x-100=0\] |
\[\Rightarrow \] \[{{x}^{2}}-25x+4x-100=0\] |
\[\Rightarrow \] \[x\,\,(x-25)+4\,\,(x-25)=0\] |
\[\Rightarrow \] \[(x-25)(x+4)=0\] |
\[\Rightarrow \] \[x=25,\]\[-\,\,4\] |
Since number is positive |
\[\therefore \] \[x=25\] |
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