question_answer

  The smallest number, which should be added to 756896 so as to obtain a multiple of 11, is [SSC CGL Tier II, 2017]

A) 1

B) 2

C) 3

D) 5

Correct Answer: C

Solution :

[c]

Here, we see that remainder is 96, which is not divisible by 11. If we add 3 in it, then it would become 99 and it is divisible by 11.

Hence, number also would be divisible by 11 i.e., number will be multiple of 11.

\[\therefore \]      Required smallest number = 3