A) 9
B) 10
C) 12
D) 18
Correct Answer: C
Solution :
[c] Let, first number \[=x\] and second number \[=y\] According to the question, |
\[xy=48\] ...(i) |
and \[x=\frac{2+5\times 2}{3}=\frac{2+10}{3}\] |
\[x=\frac{12}{3}-4\] \[\Rightarrow \]\[x=4\] |
Now, putting the value of x in Eq. (i), we get |
\[4\times y=48\]\[\Rightarrow \]\[y=\frac{48}{4}=12\]\[\Rightarrow \]\[y=12\] |
\[\therefore \] Second number = 12 |
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