A) 1
B) 2
C) 5
D) 7
Correct Answer: D
Solution :
| [d] Given, \[{{(4387)}^{245}}\times {{(621)}^{72}}\] To find the unit digit, we have to divide the index of given numbers by 4. In \[245\div 4,\] then remainder \[=1\] and In \[72\div 4,\] then remainder \[=0\] (When remainder comes 0, the index would be 4.) Hence, \[{{(4387)}^{1}}\times {{(621)}^{4}}\] \[={{7}^{1}}\times {{1}^{4}}=7\times 1=7\] |
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