A) 74
B) 78
C) 80
D) 90
Correct Answer: C
Solution :
| [c] Let the numbers be a and b. Then, \[ab=1575\] ...(i) and \[\frac{a}{b}=\frac{9}{7}\] \[\Rightarrow \] \[a=\frac{9b}{7}\] Putting this value in Eq. (i), we get \[\frac{9b}{7}\times b=1575\] \[\Rightarrow \] \[{{b}^{2}}=1575\times \frac{7}{9}\] \[\Rightarrow \] \[{{b}^{2}}=175\times 7={{5}^{2}}\times {{7}^{2}}\] \[\Rightarrow \] \[b=35\] \[\therefore \] \[a=\frac{9}{7}\times 35\] = 45 Thus, sum of the numbers \[=a+6=45+35=80\] |
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