A) 24
B) 32
C) 40
D) 28
Correct Answer: D
Solution :
| [d] Let the two consecutive odd numbers be x and \[(x+2).\] Then, according to the question, \[{{(x)}^{2}}+{{(x+2)}^{2}}=394\] \[\Rightarrow \] \[{{x}^{2}}+{{x}^{2}}+4+4x=394\] \[\Rightarrow \] \[2{{x}^{2}}+4x=390\] \[\Rightarrow \] \[{{x}^{2}}+2x=195\] \[\Rightarrow \] \[x\,\,(x+2)=195=13\times 15\] \[\Rightarrow \] \[x=13\] Thus, sum of the numbers \[=x+(x+2)\] \[=13+15\] \[=28\] |
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