A) \[\frac{4a-{{a}^{2}}}{a}=3\]
B) \[\frac{4b-2a}{{{a}^{2}}}\]
C) \[{{(a+1)}^{2}}=4b\]
D) \[\frac{a\,\,(a+2)}{b}=4\]
Correct Answer: D
Solution :
[d] Since, divisor \[=a\] Therefore, quotient \[=\frac{a}{4}\] and remainder \[=\frac{a}{2}\] \[\therefore \] \[b=a\times \frac{a}{4}+\frac{a}{2}\] \[\Rightarrow \] \[b=\frac{{{a}^{2}}+2a}{4}\]\[\Rightarrow \]\[b=\frac{a\,\,(a+2)}{4}\] |
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