A) \[\frac{1}{4}\]
B) \[\frac{7}{10}\]
C) \[\frac{8}{11}\]
D) \[\frac{5}{8}\]
Correct Answer: D
Solution :
[d] Let numerator be x. Then, denominator \[=(x+3)\] \[\frac{x+7}{(x+3)-2}=2\]\[\Rightarrow \]\[(x+7)=2\,\,(x+1)\] \[\therefore \] \[x=5\] \[\therefore \] Numerator \[=5\] and Denominator \[=(5+3)=8\] Hence, fraction \[=\frac{5}{8}\] |
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