A) 34
B) 35
C) 36
D) 37
Correct Answer: A
Solution :
\[a,b,c,d\in I,b\ne 0,d\ne 0\] ...(1) Here, \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\] \[ad+bc,bd\in I,bd\ne 0.\] And \[ab=\frac{1}{9-8}=1\]
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