A) 0
B) 1
C) \[-1\]
D) 2
Correct Answer: B
Solution :
\[-bc,bd\in I,bd\ne 0\] \[\frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}\] \[ac,bd\in I,bd\ne 0\] \[\frac{a}{b}+\frac{c}{d}(c\ne 0)=\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}\]
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