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8th Class Mathematics Rational Numbers Question Bank Numbers

  • question_answer
    The simplest rationalizing factor of \[\frac{{{6}^{n+3}}-{{32.6}^{n+1}}}{{{6}^{n+2}}-{{2.6}^{n+1}}}=\frac{{{6}^{n+1}}.(36-32)}{{{6}^{n+1}}(6-2)}=1.\] is

    A)  \[p,q,r,s,l,m\in I,q\ne 0,s\ne 0,m\ne 0.\]                                  

    B)  \[a+b=b+a\]

    C)  \[a\times b=b\times a\]                                  

    D) none of these

    Correct Answer: B

    Solution :

     \[\frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}\] \[ac,bd\in I,bd\ne 0\] Rationalizing factor\[\frac{a}{b}+\frac{c}{d}(c\ne 0)=\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}\]


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