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JEE Main & Advanced Physics Atomic Physics Question Bank Numerical Value Type Questions - Atoms

  • question_answer
    Taking the wavelength of first Balmer line in hydrogen spectrum \[\left( n=3\text{ }to\text{ }n=2 \right)\] as 660 nm, the wavelength (in nm) of the \[{{2}^{nd}}\] Balmer line (n = 4 to n = 2) will be;

    Answer:

    488.9


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