JEE Main & Advanced Physics Atomic Physics Question Bank Numerical Value Type Questions - Atoms

  • question_answer
    An excited \[H{{e}^{+}}\] ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength \[\lambda ,\]energy \[E=\frac{1240eV}{\lambda (in\,\,nm)}\]

    Answer:

    5


You need to login to perform this action.
You will be redirected in 3 sec spinner