question_answer

An organic compound undergoes first - order decomposition. The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are \[{{t}_{1/8}}\] and \[{{t}_{1/10}}\] respectively. What is the value of \[\frac{\left[ {{t}_{1/8}} \right]}{\left[ {{t}_{1/10}} \right]}\times 10\] ? \[\left( take{{\log }_{10}}2=0.3 \right)\]

Answer:

9.00