JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Numerical Value Type Questions - Circular Motion

  • question_answer
    A particle moves in a circle with a uniform speed, when it goes from a point A to a diametrically opposite point B, the momentum of the particle changes by \[{{\vec{P}}_{A}}-{{\vec{P}}_{B}}=2kg-m/s\left( {\hat{j}} \right)\]and the centripetal force acting on it changes by \[{{\vec{F}}_{A}}-{{\vec{F}}_{B}}=8N\left( {\hat{i}} \right)\] where \[\hat{i},\]\[\hat{j}\] are unit vectors. Find the angular velocity (in rad/s) of the particle.

    Answer:

    4.00


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