question_answer

In a communication system operating at wavelength 800 nm, only one per cent of source frequency is available as signal bandwidth. The number of channels accommodated for transmitting TV signals of bandwidth 6 MHz are (Take velocity of light \[c=3\times {{10}^{8}}m/s,\] \[h=6.6\times {{10}^{-34}}J-s\])

Answer:

\[\left( 6.25\times {{10}^{5}} \right)\]