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JEE Main & Advanced Mathematics Limits, Continuity and Differentiability Question Bank Numerical Value Type Questions - Continuity and Differentiability

  • question_answer
    Let \[f\left( x \right)={{\left( \sin x \right)}^{\frac{1}{\pi -2x}}},x\ne \frac{\pi }{2}\]If \[f\left( x \right)\]is continuous at \[x=\frac{\pi }{2}\]then find the value of\[f\left( \frac{\pi }{2} \right)\].

    Answer:

    1.00


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