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JEE Main & Advanced Mathematics Differential Equations Question Bank Numerical Value Type Questions - Differential Equations

  • question_answer
    Let \[y=y(x)\] be  the solution of the differential equation, \[{{({{x}^{2}}+1)}^{2}}\frac{dy}{dx}+2x({{x}^{2}}+1)y=1\] such that \[y(0)=0.\] If \[\sqrt{a}\,\,y(1)=\pi ,\] then the value of  'a'  is

    Answer:

    64


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