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JEE Main & Advanced Mathematics Differential Equations Question Bank Numerical Value Type Questions - Differential Equations

  • question_answer
        The solution of the differential equation \[x\frac{dy}{dx}+2y={{x}^{2}}\]\[(x\ne 0)\] with \[y(1)=1,\] is of the form, \[y=\frac{{{x}^{2}}}{k}+\frac{3}{k}{{x}^{2}}.\] Then, find the value of k.

    Answer:

    4


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