JEE Main & Advanced
Mathematics
Differential Equations
Question Bank
Numerical Value Type Questions - Differential Equations
question_answer
The solution of the differential equation \[x\frac{dy}{dx}+2y={{x}^{2}}\]\[(x\ne 0)\] with \[y(1)=1,\] is of the form, \[y=\frac{{{x}^{2}}}{k}+\frac{3}{k}{{x}^{2}}.\] Then, find the value of k.