question_answer

Two blocks A and B masses \[{{m}_{A}}=1\,kg\] and \[{{m}_{B}}=3kg\] are kept on the table as shown in figure. The coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F (in newton) that can be applied on B horizontally, so that the block A does not slide over the block B is: \[\left[ Take\text{ }g=10\,m/{{s}^{2}} \right]\]

Answer:

16