question_answer

A particular 100-octane aviation gasoline used 1 cc of \[{{\left( {{C}_{2}}{{H}_{5}} \right)}_{4}}Pb,\] of density 1.66 gm/cc, per litre of gasoline. \[{{({{C}_{2}}{{H}_{5}})}_{4}}Pb,\] is made as follows : \[4\,\,{{C}_{2}}{{H}_{5}}Cl\,\,+\,\,4NaPb\,\,\to \,\,{{\left( {{C}_{2}}{{H}_{5}} \right)}_{4}}Pb\,\,+\,\,4NaCl\] How many gram of \[{{C}_{2}}{{H}_{5}}Cl\]is needed to make enough \[{{({{C}_{2}}{{H}_{5}})}_{4}}Pb\] for 10 litre of gasoline, (atomic mass of \[Pb\,\,=\,\,206\])

Answer:

13.30