question_answer

Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at one point and moved with velocities \[3\text{ }m/s\] and \[4\text{ }m/s\] horizontally in opposite directions. The distance between the particles at the moment when their velocity vectors become mutually perpendicular is \[\frac{14}{10}\sqrt{a}.\]Find the value of a          (Question Modify)

Answer:

3.00