question_answer

Titanium metal is extensively used in aerospace industry because the metal imparts strength to structures but does not unduly add to their masses. The metal is produced by the reduction of \[TiC{{l}_{4}}(\text{l})\] which in turn is produced from mineral rutile\[Ti{{O}_{2}}(s)\]Calculate the Gibb's free energy for the following reaction \[Ti{{O}_{2}}(s)+2C{{l}_{2}}(g)\to TiC{{l}_{4}}(l)+{{O}_{2}}(g)\] Given that: \[H_{f}^{o}\] for \[Ti{{O}_{2}}(s),\] \[TiC{{l}_{4}}(l),\,C{{l}_{2}}(g)\] and \[{{O}_{2}}\,(g)\] are \[-\,944.7,-\,804.2,0.0,\,\,0.0\text{ }kJ\,mo{{l}^{-1}}\] Also \[S{}^\circ \]for \[Ti{{O}_{2}}(g),TiC{{l}_{4}}(l),\,C{{l}_{2}}(g)\] and \[{{O}_{2}}\,(g)\]are 50.3, 252.3, 233.0, 205.1 J \[mo{{l}^{-1}}{{K}^{-1}}\]respectively.

Answer:

158