question_answer

A Young's double slit interference arrangement with slits \[{{S}_{1}}\] and \[{{S}_{2}}\] is immersed in water (refractive index \[=\frac{4}{3}\] ) as shown in the figure. The positions of maximum on the surface of water are given by\[{{x}^{2}}={{p}^{2}}{{m}^{2}}{{\lambda }^{2}}-{{d}^{2}}\], where \[\lambda \] is the wavelength of light in air (refractive index = 1), 2d is the separation between the slits and m is an integer. The value of p is

Answer:

3