question_answer

The potential energy of a particle is determined by the expression\[U=a\left( {{x}^{2}}+{{y}^{2}} \right)\], where \[\alpha \] is a positive constant. The particle begins to move from a point with the coordinates (3, 3) (m), only under the action of potential field force. Then its kinetic energy T at the instant when the particle is at a point with the coordinates (1, 1) (m) is 32\[\alpha /n\]. Find n.

Answer:

2.00