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JEE Main & Advanced Physics Question Bank Oblique Projectile Motion

  • question_answer
    A projectile fired with initial velocity \[u\] at some angle \[\theta \] has a range \[R\]. If the initial velocity be doubled at the same angle of projection, then the range will be

    A)             \[2R\]

    B)               \[R/2\]

    C)             \[R\]    

    D)             \[4R\]

    Correct Answer: D

    Solution :

                    \[R=\frac{{{u}^{2}}\sin 2\theta }{g}\,\,\therefore R\propto {{u}^{2}}\]. If initial velocity be doubled then range will become four times.


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