A) 5 : 4
B) 5 : 2
C) 5 : 1
D) 10 : 1
Correct Answer: A
Solution :
\[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] and \[T=\frac{2u\sin \theta }{g}\] So \[\frac{H}{{{T}^{2}}}=\frac{{{u}^{2}}{{\sin }^{2}}\theta /2g}{4{{u}^{2}}{{\sin }^{2}}\theta /{{g}^{2}}}=\frac{g}{8}=\frac{5}{4}\]You need to login to perform this action.
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