A) \[10\,m/{{\sec }^{2}}\]
B) \[5m/{{\sec }^{2}}\]
C) \[20\,\,m/{{\sec }^{2}}\]
D) \[2.5\,\,m/{{\sec }^{2}}\]
Correct Answer: A
Solution :
\[{{a}_{x}}=\frac{d}{dt}({{v}_{x}})=0\], \[{{a}_{y}}=\frac{d}{dt}({{v}_{y}})=-10\ m/{{s}^{2}}\] \ Net acceleration a =\[\sqrt{a_{x}^{2}+a_{y}^{2}}\]=\[\sqrt{{{0}^{2}}+{{10}^{2}}}\]=10m/s2
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