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JEE Main & Advanced Physics Question Bank Oblique Projectile Motion

  • question_answer
    The greatest height to which a man can throw a stone is \[\sqrt{\frac{F}{m\,r}}\]. The greatest distance to which he can throw it, will be

    A)             \[2\,\pi \,{{r}^{2}}/T\]         

    B)             \[\upsilon ,\,\upsilon \text{ and }\upsilon \]

    C)             \[2h\]   

    D)             \[3h\]

    Correct Answer: C

    Solution :

                    For greatest height \[\theta =90{}^\circ \]                   \[{{H}_{\max }}=\frac{{{u}^{2}}{{\sin }^{2}}(90{}^\circ )}{2g}=\frac{{{u}^{2}}}{2g}=h\] (given)                   \[{{R}_{\max }}=\frac{{{u}^{2}}{{\sin }^{2}}2(45{}^\circ )}{g}=\frac{{{u}^{2}}}{g}=2h\]


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