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JEE Main & Advanced Physics Question Bank Oblique Projectile Motion

  • question_answer
    A ball is projected with kinetic energy \[E\]at an angle of \[{{45}^{o}}\] to the horizontal. At the highest point during its flight, its kinetic energy will be                                  [MP PMT 1994; CBSE PMT 1997, 2001; AIEEE 2002; Pb. PMT 2004; Orissa PMT 2004]

    A)             Zero    

    B)             \[\frac{E}{2}\]

    C)             \[\frac{E}{\sqrt{2}}\] 

    D)             \[E\]

    Correct Answer: B

    Solution :

                    \[E'=E{{\cos }^{2}}\theta =E{{\cos }^{2}}(45{}^\circ )=\frac{E}{2}\]


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