question_answer

A particle of mass \[m\] is projected with velocity \[v\] making an angle of \[{{45}^{o}}\]with the horizontal. The magnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where \[g=\] acceleration due to gravity) [MP PMT 1994; MP PET 2001; Pb. PET 2004]

A)             Zero    

B)             \[m{{v}^{3}}/(4\sqrt{2}g)\]

C)             \[m{{v}^{3}}/(\sqrt{2}g)\]

D)               \[m{{v}^{2}}/2g\]